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13.93x^2+14.93x+4=0
a = 13.93; b = 14.93; c = +4;
Δ = b2-4ac
Δ = 14.932-4·13.93·4
Δ = 0.0249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(14.93)-\sqrt{0.0249}}{2*13.93}=\frac{-14.93-\sqrt{0.0249}}{27.86} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(14.93)+\sqrt{0.0249}}{2*13.93}=\frac{-14.93+\sqrt{0.0249}}{27.86} $
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